5^x=7(1/625)^2x=13

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Solution for 5^x=7(1/625)^2x=13 equation: 



5^x=7(1/625)^2x=13

We move all terms to the left:

5^x-(7(1/625)^2x)=0



Domain of the equation: 625)^2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5^x-(7(+1/625)^2x)=0

We multiply all the terms by the denominator


5^x*625)^2x)-(7(+1=0

Wy multiply elements

3125x^2+1=0

a = 3125; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·3125·1
Δ = -12500
Delta is less than zero, so there is no solution for the equation

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